8x^2+158x-40=0

Solution for 8x^2+158x-40=0 equation:

8x^2+158x-40=0

a = 8; b = 158; c = -40;
Δ = b2-4ac
Δ = 1582-4·8·(-40)
Δ = 26244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26244}=162$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(158)-162}{2*8}=\frac{-320}{16}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(158)+162}{2*8}=\frac{4}{16}
=1/4
$